Analysis

The analysis of this project's primary intent was to estimate an average force created by the pressure difference after the can had been placed in the ice bath. The following gives a description of this anaylsis.

Velocities

Picture (filename)

Velocities (m/s)

Regression Line

Slope =average acceleration

Cans1095.jpg (amit)

.506, 1.59, and 5.63

Y=427x-1.27

427m/s/s

Cans3009.jpg (amit)

.671 and 1.98

Y=327x+.0165

327m/s/s

Cans1095.jpg (rohit)

.61, 1.36, and 5.29

Y=390x-1.09

390m/s/s

Cans4006.jpg (rohit)

.841, 1.00, and 9.45

Y=1150x-2.6

1150m/s/s

Cans3009.jpg (rob)

.600 and 2.20

Y=400x - .2

400m/s/s

Cans4008.jpg (rob)

.350, 1.40, and 4.10

Y=470x - .86

470m/s/s

The second part of the analysis was the force analysis:

Analysis of Force using Diagram:

If we assume that the air pressure is the only force acting on the part of the can in bold, we can isolate that part of the can and do a simple force problem.

Fnet = N+mg = ma

N = ma – mg

N = (.004 kg)(400 m/s/s) – (.004 kg)(9.8 m/s/s)

N = 1.6 Newtons

The remaining calculations are just conversions and simple mathematics:

The surface area of the can = radius˛(pi)

Surface area = (.00325 m) ˛(3.14)

Surface area = 3.3 x 10^-5 m˛

Air pressure = force/surface area = (1.6 Newtons)/(3.3 x 10^-5 m˛)

Air pressure = 48,000 Pascals

Conversion from Pascals to psi = Pascals/Conversion factor

(48,000 Pascals)/(6.894 x 10^3 Pascals/psi) = 7.0 psi

Percent difference from accepted value:

((14.7 psi)-(7.0 psi))/(14.7 psi)*100 = 52% difference